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To find the displacement of the particle, we need to integrate the velocity function over the given time interval. The displacement, denoted as s(t), can be found by integrating the velocity function v(t) with respect to time from t = 0 to t = 4: s(t) = ∫(v(t)) dt = ∫(3t^2 - 6t + 2) dt Integrating term by term, we get: s(t) = t^3 - 3t^2 + 2t + C Now, to find the displacement from t = 0 to t = 4, we evaluate s(t) at t = 4 and subtract s(t) evaluated at t = 0: Displacement = s(4) - s(0) = (4^3 - 3(4)^2 + 2(4) + C) - (0^3 - 3(0)^2 + 2(0) + C) = (64 - 48 + 8 + C) - (0 - 0 + 0 + C) = 24 Therefore, the displacement of the particle from t = 0 to t = 4 seconds is 24 units.